5x^2+4x-44=0

Solution for 5x^2+4x-44=0 equation:

5x^2+4x-44=0

a = 5; b = 4; c = -44;
Δ = b2-4ac
Δ = 42-4·5·(-44)
Δ = 896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{896}=\sqrt{64*14}=\sqrt{64}*\sqrt{14}=8\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8\sqrt{14}}{2*5}=\frac{-4-8\sqrt{14}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8\sqrt{14}}{2*5}=\frac{-4+8\sqrt{14}}{10}
$